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Seat No.: Enrolment
GUJARAT TECHNOLOGICAL UNIVERSITY
ME SEMESTER II EXAMINATION WINTER 2018
Subject Code: 1722007 Date: 15-Dec-2018
Subject Name: Advanced Steel Structures
Time: 2.30 pm to 5.00 pm Total Marks: 70
Instructions:
1. Attempt all questions.
2. Make suitable assumptions wherever necessary.
3. Figures to the right indicate full marks.
4. IS800: 2007, IS875 (Part IS1893 (Part 2002 SP 1 and or Steel table are allowed to carry in exam hall.
Q.1

Calculate design wind forces on a steel multi-storey building 60m tall and plan size 10mx20m to be constructed in Chennai (Madras). Assume average storey height to be 3.0m. The frames are to be spaced at 5m c/c in both directions.
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Q.2

Using schematic diagram explain structural design process.
07

List and explain types of connections.
07
OR

Explain high-rise structural systems with neat sketches which can resist lateral loads and discuss various methods of approximate analysis for the same.
07
Q.3

A two span continuous beam ABC has span length AB=5m and BC=5m and carries a factored udl of 15kN/m completely covering the spans AB BC. A C are fixed supports. Find the section modulus required for section of the beam needed. Assume yield stress for the material as 250 N/mm2.
07

Explain the calculation of earthquake load for a multi storey building as per IS1893.
07
OR
Q.3

Determine the collapse load using plastic analysis for a frame ABCD for the following are vertical members with lengths 6m, A D are the fixed supports. BC is a horizontal member with 8m length. The frame carries a horizontal rightward force at point B a central vertical concentrated load on member BC. The frame has uniform plastic moment MP.
07

A four storey one bay steel moment resisting frame having 3 m storey height is located in Guwahati (Seismic Zone V).The Soil conditions are medium and the damping is 5 Determine the seismic load as per IS1893-2002 on the frame. Take lumped mass on roof =1500 KN and lumped mass on all other floors 2500 KN. This frame is to be used as office building with plan dimensions as 6m x 5m.
07
Q.4

A suspension cable of 120m horizontal span is supported at the same level. It is subjected to a uniformly distributed load of 20kN/m (horizontal). If the maximum tension in the cable is limited to 4500kN, calculate the minimum central dip needed.
07

Design a suitable beam-column assuming fy=250 N/mm2 and effective length of column as 0.8L along both the axes for
a factored axial load 500 kN
a factored bending moment =1500 kN m
a factored shear force 600 kN
07
OR
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Q.4

Design a welded seat angle connection between a beam ISMB250 and flange of column ISHB300 for a reaction of beam 150kN, assuming Fe410 grade steel (fy=250Mpa) and field welding.
07

Design a bolted web cleat connection for an ISMB500 and a coped beam of size ISMB350 using bolts of 20mm diameter and grade 4.6. The factored load reaction is 250kN.
07
Q.5

In a plate girder of through type bridge, carrying a single broad gauge track, the cross girders are provided at 4.0 m c/c. The stringers are placed at 2 m c/c. Using the data given below, design the stringers.
Size of slipper 2.8 m x 250 mm x 250 mm are provided 450 mm c/c.
The spacing between the main girder 4 m.
Equivalent udl for 4.0 m for BM per track 400 KN
Equivalent udl for 4.0 m for SM per track 500 KN
The impact factor for 4 m span 1.0. unit wt. of timber=7.5 KN/m2.
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OR
Q.5

A pratt truss girder through bridge is provided for single broad gauge track. The effective span of bridge is 21m (7panels 3m and height 5m. The stringers are spaced 2m between centerline. The main girders are provided at a spacing of 5m between their centerlines.
The total Dead load per girder=10kN/m,
EUDLL (Equivalent Uniformly Distributed Live Load) for 21m span for each track=1600kN.
Design critical top chord member OR Critical Bottom chord member for the data given above. Consider the impact factor as 0.57
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